Re: mon question/problem?

Use printf("%4d-%02d-%02d",$x['year']...etc) instead of your print line. I believe %02d prints an integer padded with 0's. I could be wrong, but that's close. On Wed, 16 Apr 2003 Khristopher_Klaich@nywd.uscourts.gov wrote: > Hello I have the below code that creates a drop down box which lists > business days in the future. If I echo out the $form_date variable I get > 2003-17-4 which from what I can tell is how it should work. I then have > a date field in a mysql database that I am trying to insert this variable > in and it is not working and I am guessing it is because that the 4 does > not have a leading 0???? Can anyone give me an idea how to modify my code > to make it have the leading 0 or tell me what is wrong with the code > below? -Thanks-Khris > > $x=getdate(); > print "<select name=\"form_date\" id=\"form_date\">"; > for($i=1;$i<=170;$i++) > { > $x=getdate(mktime(0,0,0,$x['mon'],$x['mday']+1,$x['year'])); > if (($x['wday'] != 0) && ($x['wday'] != 6)) > print "<option > > value=".$x['year']."-".$x['mday']."-".$x['mon'].">".date("F > d,Y",mktime(0,0,0,$x['mon'],$x['mday']-1,$x['year'])); > } > print "</select>"; --------------------------------------------------------------------------- Peter Beckman Internet Guy beckman@purplecow.com http://www.purplecow.com/ ---------------------------------------------------------------------------