Re: Date Formatting in PHP

At 05:23 PM 6/10/2003 -0400, David Shugarts wrote:

I have a simple need to reformat a variable coming in as $DatePick, brought forward from a MySQL select in the format:

    2003-11-18

I need to convert it to the format

    November 18, 2003
try the "dice-n-slice" method.  use substr and concatenation to build $DayReport from the current value of $DatePick.

I am trying to avoid having to mess with the MySQL select statement, as the output is being passed through several documents. So I need to do it within PHP. I tried making a conversion like

    $DayReport = date ("F d, Y", $DatePick);

But the value of $DayReport is neither correct nor does it change when $DatePick changes. For instance, in this example, the $DatePick value of "2003-11-18" gets converted to "December 31, 1969." TIA Dave Shugarts -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php