RE: [PHP-DB] Problem with select-tag within a php-script

the select has to be a name and not the id the id has to be within the option value! -----Original Message----- From: Ruprecht Helms [mailto:rhelms@mayn.de] Sent: woensdag 2 juli 2003 15:51 To: php-db@lists.php.net Subject: [PHP-DB] Problem with select-tag within a php-script Hi, I've some trouble with a select-tag in a php-script. In a database should be written the ID of a table, the user could select the recordset by the Name. My problem is that the fieldentry of the selecttag is not transfered to the executionscript. The different Names within the recordset are shown correctly. Here my listing <? mysql_connect("localhost","root"); $result=mysql_db_query("chorportal","SELECT * FROM choere ORDER BY Name"); echo "<select value='chorid'>"; while($row = mysql_fetch_object($result)) { echo "<option value=\'.$row->ID.\'>"; echo $row->Name; echo "</option>"; } echo "</select>"; ?> Regards, Ruprecht -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php