RE: [PHP-DB] weird php error

On 29 August 2003 06:39, OpenSource wrote: > Hi guys, > > This is weird to me.. > I got this script > --------------------------------------------------- <?php > > if ($_GET[login] == 'forgot') > { > echo "Sorry I forgot my password"; > } else { echo "you are good to go"; } > > > > ------------------------------------------------- > when ran, it gives me this error > > ------------------------------------------------ > Notice: Use of undefined constant login - assumed 'login' in > G:\Inetpub\wwwroot\test\index.php on line 3 This is because you haven't quoted the array subscript -- PHP thinks you're trying to refer to a constant called login, but on not finding that assumes that you meant the string 'login' instead. To suppress this notice, supply the subscript correctly as a string: if ($_GET['login'] == 'forgot') > > Notice: Undefined index: login in G:\Inetpub\wwwroot\test\index.php > on line 3 This means that there was no login= parameter on the URL that called this script. If this is a permissible condition, you need to allow for it in your code. One way is simply to suppress the error message with the @ operator: if (@$_GET['login'] == 'forgot') Another is to do more explicit checking: if (isset($_GET['login']) && $_GET['login'] == 'forgot') Which you use is really down to personal preference. Cheers! Mike --------------------------------------------------------------------- Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: m.ford@lmu.ac.uk Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211