Re: SELECT COUNT - result from two tables
| From: | CPT John W. Holmes | Date: | Thu, 06 Nov 2003 13:20:04 +0000 |
| Subject: | Re: SELECT COUNT - result from two tables | ||
| References: | 1 2 3 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-31475@lists.php.net to get a copy of this message | ||
From: "Boyan Nedkov" <k24d88@home.nl>
> Putting more than one table in the FROM clause means tables are joined,
> then at least following problems could arise:
>
> - using WHERE clause you can have empty recordset returned and then
> COUNT conflicts with it because there is actually no any data to be
> returned;
There won't be a conflict, COUNT(*) will just return zero. When you use
COUNT(*) there will _always_ be a row returned, either zero or the count.
> - joining two (or more) tables without using aliases to the equally
> named columns in the SELECT/WHERE/COUNT clauses will produce error
> message instead of expecting data;
You don't need an alias and the columns don't have to be equally named, but
yes, you have to "join" them somehow against some column. The original query
had this.
> - COUNT(*) wont work if u have equal table names in the tables;
I have no idea what you mean by that.
---John Holmes...