Display Mysql Result in drop down list

From: Date: Tue, 23 Dec 2003 04:52:30 +0000
Subject: Display Mysql Result in drop down list
Groups: php.db 
Request: Send a blank email to php-db+get-32167@lists.php.net to get a copy of this message
Hi all, Right now I'm trying to retrieve one of the column "tutor_name" and display al the tutor's name in a drop down list. The problem now is, the drop down list only manage to display 1 record from that row instead of all tutor's name under "tutor_name" column...wonder where the problem lies?? Hope to get some help soon. Below is a snip of the code: Drop me a msg if anyone needs the entire code. <SELECT NAME="tutor_name" class="textarea"> <? $sql = mysql_query("SELECT DISTINCT tutor_name FROM tutor "); if ($row = mysql_fetch_array($sql)) { print "<OPTION VALUE=\"$tutor_name\" SELECTED>" .$row ["tutor_name"]. "</option>"; } $result = $db->query($sql); ?> </select> Thanks in advance =) Irin.

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