Re: Brick Codes
| From: | Ricardo Lopes | Date: | Tue, 17 Feb 2004 10:09:31 +0000 |
| Subject: | Re: Brick Codes | ||
| References: | 1 2 3 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-32976@lists.php.net to get a copy of this message | ||
I think this is what you want:
SELECT *
FROM Locations L, Brick B
WHERE (LEFT(L.'Post Code',3) = LEFT(B.Brick,3))
If you want to select 4 characters change the 3 to 4 :-)
Avoid using spaces and special characters in your column it may give you
problems.
----- Original Message -----
From: "Shaun" <shaun@mania.plus.com>
To: <php-db@lists.php.net>
Sent: Tuesday, February 17, 2004 10:04 AM
Subject: Re: [PHP-DB] Brick Codes
> Thanks for your reply,
>
> but what I actually need to do is compare the first 3 or 4 digits of the
> postcode stored in locations to the same in the Brick table...
>
>
> "Ricardo Lopes" <lopes@elevaconsult.pt> wrote in message
> news:003501c3f537$ad240050$5501000a@pnpgdom.net...
> > That may depend of what database server you are using, for mysql you can
> > use:
> >
> > ........ WHERE (LEFT('Brick',3) = LEFT(Post Code,3))
> >
> > If you are using other dbserver, check your manual.
> >
> > ----- Original Message -----
> > From: "Shaun" <shaun@mania.plus.com>
> > To: <php-db@lists.php.net>
> > Sent: Monday, February 16, 2004 10:45 PM
> > Subject: [PHP-DB] Brick Codes
> >
> >
> > > Hi,
> > >
> > > I have a table of Locations around the country. My system produces
> reports
> > > based on these Locations. I also have a table containing Brick Codes
> e.g.
> > >
> > > Brick Post Code
> > > AB51 AB51
> > > AB52 AB52
> > > AB55 AB55
> > > AB56 AB56
> > > AL01 AL1
> > > AL02 AL2
> > > AL03 AL3
> > > AL04 AL4
> > >
> > >
> > > How can I compare the first 3 or 4 letters of the postcode in the
> > Locations
> > > table to the corresponding entry in the Brick Codes table so I can add
> it
> > to
> > > my report?
> > >
> > > Thanks for your help
> > >
> > > --
> > > PHP Database Mailing List (http://www.php.net/)
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> > >
> > >
>
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