Re: SELECT

From: Date: Thu, 04 Mar 2004 12:22:57 +0000
Subject: Re: SELECT
References: 1 2  Groups: php.db 
Request: Send a blank email to php-db+get-33292@lists.php.net to get a copy of this message
Hi I made this query $sql = "SELECT * FROM users WHERE FIND_IN_SET( 2, access ) > 0 "; $result = mysql_query($sql); $numRows = mysql_num_rows($result); for ($row =1; $row <= $numRows; $row++) { $rowArray = mysql_fetch_array($result); $access1 = $rowArray[1]; if ($access1 =='2'){ echo "Access is 2 "; } else { echo "acces is not 2"; } } I get always access not 2 how can I make this If works "Ignatius Reilly" <ignatius.reilly@free.fr> wrote in message news:002d01c401e0$8ec16e80$0100a8c0@server... > SELECT > ... > FROM users > WHERE FIND_IN_SET( 2, values ) > 0 > > Ignatius > _________________________ > ----- Original Message ----- > From: "peppe" <peppe1001@hotmail.com> > To: <php-db@lists.php.net> > Sent: Thursday, March 04, 2004 12:28 > Subject: [PHP-DB] SELECT > > > > Hi I have a table users with columns name email and access > > In email I have values test@test.com etc in access I have values > 1,2,3,4,7,8 > > How can I filter value 2 ? > > Beacause I need only users with value 2 to send email > > Greetings > > > > -- > > PHP Database Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > >

« previous php.db (#33292) next »