Re: Stuck on basic concept, how to use a list selection?

From: Date: Fri, 19 Mar 2004 20:07:37 +0000
Subject: Re: Stuck on basic concept, how to use a list selection?
References: 1  Groups: php.db 
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From: "Doug F" <stonehusky@metrocast.net> > Populate a dropdown list with values from a MySQL db (done and working). > Use the selected value as the 'where' clause in a second query. > Return the results and display them to the user. > > Any pointers are appreciated - noob^3 (html, mysql, and php). > > Doug > > Code that I'm using: > > <html> > <body> > <?php > > // connect to db > $db = mysql_connect("localhost"); > mysql_select_db("test",$db); > > // build query > $sitequery = "SELECT site from sitedata order by site"; > > // generate result set > $siteresult = mysql_query($sitequery); > > // use results > echo "Select a site from the list below: <br><br><select > name='site'>"; > while($siterow = mysql_fetch_array($siteresult)) > echo "<option value='".$siterow["site"]."'>" > $siterow["site"]."</option>"; > echo "</select></td>"; When the form is submitted, the value chosen will be in $_REQUEST['site'] (or $_GET['site'] or $_POST['site'], depending upon your form method). Then just create your query: $query = "SELECT * FROM sitedata WHERE site = '{$_REQUEST['site']}'"; If magic_quotes_gpc is not ON, then you'll want to run mysql_escape_string() on the value first. $site = mysql_escape_string($_REQUEST['site']); $query = "SELECT * FROM sitedata WHERE site = '$site'"; See the recent threads on SQL Injection for a reason why. :) ---John Holmes...

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