Re: Subject: putting strings together with a linefeed

You should appreciate there is a difference between using double quotes and single quotes around a string. So you can't say print('what up doc $mycarriagereturnvariable'); and expect it to output the value of $mycarriagereturnvariable. Next, you *can* use this construct within *double* quotes. Finally, there are special characters - "Escaped characters" you can use with PHP to generate a carriage return : These include :

\t      : Tab character
\r      : Carriage return character
\n      : Newline character

So your string should be : print("what up doc\r\n"); Hope that helps Neil. At 16:23 16/04/2004 +0000, you wrote:

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Date: Fri, 16 Apr 2004 11:23:51 -0500 Message-ID: <AED295B4597E884A82081E567887C4F30E1C90@bluebird2.home.ku.edu> From: "Hull, Douglas D" <ddhull@ku.edu> To: "Note To php mysql List (E-mail)" <php-db@lists.php.net> Subject: putting strings together with a linefeed For example, say I have a variable $mytext = 'what up doc'. Now I want to add the text 'not much' to the end of this variable. But I want to place a return or linefeed after the original text so when I echo $mytext it looks like: what up doc not much I tried: $mytext = 'what up doc';

$mytext .= chr(10) . 'not much';    I also tried chr(13)

10 is linefeed and 13 is carriage return. Thanks for your previous help as well. Doug

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