Displaying Date from Value in MySQL DB
| From: | Justin @ Dreaming in TO | Date: | Tue, 20 Apr 2004 18:27:30 +0000 |
| Subject: | Displaying Date from Value in MySQL DB | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-33984@lists.php.net to get a copy of this message | ||
Hey All,
Looking to try to figure at small problem.
This is the SQL query I am using to show the next event on a page:
SELECT ditoevents.eventstatus, ditoevents.eventdate, DATE_FORMAT(ditoevents.eventdate, '%a, %b %d %Y'), ditoevents.eventtime, ditoevents.eventlocation, ditoevents.topic, ditoevents.presenter
FROM ditoevents
WHERE ditoevents.eventstatus = 'next'
This is the structure of the table in the MySQL db:
CREATE TABLE ditoevents (
ID char(3) NOT NULL default '',
eventID char(2) NOT NULL default '',
eventstatus varchar(4) NOT NULL default '',
eventdate date NOT NULL default '0000-00-00',
eventtime time NOT NULL default '00:00:00',
eventlocation text NOT NULL,
topic text NOT NULL,
presenter text NOT NULL
) TYPE=MyISAM;
The problem is, the date value that's being pulled from the DB is being displayed as 2004-05-12. I would like the date to be displayed as, Wednesday, May 12th, 2004.
How do I do this with PHP. I looked at some of the date functions, and I'm a bit confused.
Thanks,
Justin