Re: What's wrong with this IF statement?

What about removing the quotes around the numbers. if ($cat_id != 53 || $cat_id != 54 || $cat_id != 55 etc... > My IF statement should be picking up on the numbers, and if the number > matches not be displaying out the information, however I look at the > outputted page and the information is still there, what have I got wrong > on the code? > > <CODE SNIPPET> > //Show categories first > $get_cats = "select id_num, id_name, description, cat_code from > categories order by id_name"; > $get_cats_res = mysql_query($get_cats) or die(mysql_error()); > > if (mysql_num_rows($get_cats_res) < 1) > { > $display_block = "<P><em>Sorry, no categories to > browse.</em></P>"; > } > else > { > while ($cats = mysql_fetch_array($get_cats_res)) > { > $cat_id = $cats[id_num]; > if ($cat_id != "53" || $cat_id != "54" || $cat_id != "55" || > $cat_id > != "117" || $cat_id != "118" || $cat_id != "74") > { > $cat_title = strtoupper(stripslashes($cats[id_name])); > $cat_desc = stripslashes($cats[description]); > $display_block .= "<strong><a > href=$_SERVER[PHP_SELF]?cat_id=$cat_id>$cat_title > $cat_desc</a></strong><br>\n"; > while ($items = mysql_fetch_array($get_items_res)) > { > $item_id = $items[id]; > $item_num = $items[item_num]; > $item_desc = stripslashes($items[description]); > if ($item_num != "ABC-R37" || $item_num != "ABC-R42" || $item_num > != "HB-99100" || $item_num != "RO-PUMPS" || $item_num != > "ML-HDGALJUG" > || $item_num != "PFS-CAC21" || $item_num != "PFS-CO2") > { > $item_num = ltrim($item_num); > $item_num = rtrim($item_num); > $display_block .= "    <em><strong><a > href=\"catalog/$item_id.html\">$item_num</a></strong> - > $item_desc</em><br>\n"; > } > } > <END SNIPPETS> > > My assumption is that BOTH IF statements are not working correctly since > the logic is that if they are built the same they would react the same. > HELP! > > TIA! > Robert > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >