Re: SQL question!

From: Date: Tue, 04 May 2004 02:19:06 +0000
Subject: Re: SQL question!
References: 1  Groups: php.db 
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What you wrote will give you the list of users who also happen to have comments. What you really want is more like this: SELECT Users.ID, Users.UserName, Comments.Description FROM Users LEFT JOIN Comments ON Users.ID = Comments.UserID; (note that you'll need to have the UserID foreign key in your Comments table. Also, the "LEFT JOIN" phrase tells whatever sql back-end you're using that you want -all- records from the users table, regardless of whether or not they have a comment-- and any comments per user in the comments table. If you want to eliminate users who don't have comments, use an INNER JOIN instead. -Mike Forbes Bruno Braga wrote:
Hey. I have these tables. Users ( id,name,etc ) Coments : ( id , comment ) How do I do this kind of query: I thought in one thing like this but I cant figure it out. Example: Select * from users order by id desc in (select count (id) from comments) Expected result: List of users: * User1 See comments ( 32 comment in database ) * User2 See coments (13 comments in database ) * etc. thanks in advanced. Bruno


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