Re: problem....
| From: | Daniel Clark | Date: | Wed, 23 Jun 2004 00:52:49 +0000 |
| Subject: | Re: problem.... | ||
| References: | 1 2 3 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-34873@lists.php.net to get a copy of this message | ||
Sounds like it doesn't like your SQL statement. Perhaps a field or table
name is incorrect?
> Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
> result
> resource in .......
> "Daniel Clark" <dclark@nwlink.com> wrote in message
>
> news:16692.65.203.232.102.1087950853.squirrel@webmail.pacifier.com...
>> What error are you getting?
>>
>> > why doesn't this work:
>> > $pic=mysql_query('SELECT Rune, username FROM RuneRunner
>> > RuneRunner_1 WHERE (User_ID = 3)',$connection);
>> > $pic=mysql_fetch_array($pic);