Re: How to define array variable while accessing it ???

Actually I want to know how to access the variable after defining it. Like : $query="delete from feedback where id=$delete[$i]"; $deleteresult=mysql_query($query) or die("Unable to delete"); But here I am not getting any value in "$delete[$i]"-(here $i is 0,1,2,3) So what to do to access it ? I cant access the value even by $_POST['$delete[$i]'] Can any of you suggest me the sollution ? Rinku --- Torsten Roehr <roehr@zilleon.com> wrote: > "Matt M." <h.dudeness@gmail.com> wrote in message > news:7d458020040628114862c2d150@mail.gmail.com... > > > <TD><DIV ALIGN="CENTER"> <input > type="checkbox" name="<? > printf("chk_arr[%d]",$i); ?>" value="<?=$row[0]?>" > ></DIV></TD> > > > > setup your checkbox something like this: > > > > <input type="checkbox" name="delete[]" > value="<?=$row[0]? /> > > > > php will treat this as an array > > The closing php tag and quote of the value attribute > was missing: > > <input type="checkbox" name="delete[]" value="<?= > $row[0] ?>" /> > > Regards, Torsten Roehr > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > __________________________________ Do you Yahoo!? Yahoo! Mail is new and improved - Check it out! http://promotions.yahoo.com/new_mail