Re: Please help
| From: | Stuart Felenstein | Date: | Fri, 10 Sep 2004 14:49:40 +0000 |
| Subject: | Re: Please help | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-36143@lists.php.net to get a copy of this message | ||
As I said this is a code generator (dbqwiksite). So,
describing the process for creating the code is
different. The $sql is fine, as far as typos or
incorrect characterrs. I've gone through those
statement very carefully.
I've also tried to run a debug with no luck.
But I do know that there is something wrong with the
statement, since I can get a complete display of all
records, but can't search using criteria.
Below is the $sql, one I know works , though I've
tried others. VendorJobs is the table I'm querying ,
and since it's made up of values from other static
type tables I have all the joins in place.
I've also taken the tick marks out, thinking maybe it
was a style issue. I'm not sure where to go with it.
Getting a response from the company is like pretty
difficult.
VendorJobs.JobID,
VendorSignUp.CompanyName,
StaIndTypes.CareerCategories,
StaUSCities.City,
USStates.States,
VendorJobs.AreaCode,
staTaxTerm.TaxTerm,
VendorJobs.PayRate,
staTravelReq.TravelReq,
VendorJobDetails.Details,
VendorJobs.PostStart,
VendorJobs.JobTitle
FROM
VendorJobs
INNER JOIN VendorSignUp ON
(VendorJobs.VendorID = VendorSignUp.VendorID)
INNER JOIN StaIndTypes ON (VendorJobs.Industry
= StaIndTypes.CareerIDs)
LEFT OUTER JOIN StaUSCities ON
(VendorJobs.LocationCity = StaUSCities.CityID)
LEFT OUTER JOIN USStates ON
(VendorJobs.LocationState = USStates.StateID)
LEFT OUTER JOIN staTaxTerm ON
(VendorJobs.TaxTerm = staTaxTerm.TaxTermID)
INNER JOIN staTravelReq ON
(VendorJobs.TravelReq =
staTravelReq.TravelReqID)
INNER JOIN VendorJobDetails ON
(VendorJobs.JobID = VendorJobDetails.JobID)
Stuart
--- Philip Thompson <prthomp@uark.edu> wrote:
> I think everyone knows that $sql is a statement. But
> what people are
> asking is: what is that statement?! Because if there
> are "incorrect"
> characters or 's in that statement, then that can
> break your
> code/statement.
>
> ~Philip
>
> On Sep 9, 2004, at 5:49 PM, Stuart Felenstein wrote:
>
> > Just getting back to this thing. There are 3
> files
> > involved, search.php, connections.php and
> > functions.php.
> >
> > I searched through all and couldn't find the
> meaning
> > of the $sql_ext. $sql is just the sql statement
> I
> > inserted into the code.
> >
> > Great that I can't get a response from the
> company.
> > If anyone thinks it would be useful to post the
> code I
> > will. That is if anyone would want to see and look
> at
> > it.
> >
> > The weird thing is searching on one table is
> great.
> > The list (all records) works great. The problem
> > starts when I insert all my joins. Now I've
> tested
> > and retested the query and I know it's fine.
> >
> > Thank you ,
> > Stuart
> >
> >
> > --- Steve Davies <steve@sdconsulting.co.uk> wrote:
> >
> >> What's contained in $sql and $sql_ext ???
> >>
> >>
> >> Stuart Felenstein wrote:
> >>
> >>> I'm using a product called dbqwiksite pro. PHP
> >>> generator for PHP - MySQL
> >>>
> >>> The code seems to be working fine except in my
> >> search
> >>> page where I receive an "invalid query"
> >>>
> >>> $result = mysql_query($sql . " " . $sql_ext . "
> >> limit
> >>> 0,1")
> >>> or die("Invalid query");
> >>>
> >>> This is the place I where the code is taking the
> >> die
> >>> path.
> >>> I'm guessing something belongs between the
> >> quotation
> >>> marks , just not sure.
> >>>
> >>> Anyone ?
> >>>
> >>> Thank you
> >>> Stuart
> >>>
> >>>
> >>>
> >>
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