RE: [PHP-DB] How to get 2 columns to display

try this <?php for ($r=0;$products = db_fetch($productsQuery);$r++) { if (($r % 2) == 0) { echo "</tr>

	    					<tr valign=\"top\">";

}

     echo "<td align=\"center\">
     			<a href=".$base_url."products/".$category."/".$products['name_url']
						class="product_link"><img src=".$base_url."product_images/thumbs/".$products['thumb'] border="0"

width=\"159\"><br>".$products['name']."</a></td>"; } ?> bastien

From: "Aaron Wolski" <aaronjw@martekbiz.com> To: <php-db@lists.php.net> Subject: [PHP-DB] How to get 2 columns to display Date: Mon, 6 Dec 2004 08:43:21 -0500 Hi guys, I'm trying to get two columns of <td></td> to display side by side and then go to a new row. I am using this code but nothing I seem to do is working this far. <?php for ($r=0;$products = db_fetch($productsQuery);$r++) { ?>

      <td align="center"><a href="<?php echo $base_url; ?>products/<?php

echo $category; ?>/<?php echo $products['name_url']; ?>" class="product_link"><img src="<?php echo $base_url; ?>product_images/thumbs/<?php echo $products['thumb']; ?>" border="0" width="159"><br><?php echo $products['name']; ?></a></td> <?php if ((($r+1) % 2) == 0) { ?>

    </tr>
    <tr valign="top">

<?php } } ?> What is happening with this code is I am getting results like: <tr> <td>IMAGE HERE</td> <td>IMAGE HERE</td> <td>IMAGE HERE</td> <td>IMAGE HERE</td> <td>IMAGE HERE</td> </tr> What I WANT is: <tr> <td>IMAGE HERE</td> <td>IMAGE HERE</td> </tr> <td>IMAGE HERE</td> <td>IMAGE HERE</td> </tr> <td>IMAGE HERE</td> <td></td> </tr> ANY clue where I am going wrong? Thanks so much. Aaron -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php