RE: [PHP-DB] help newbies :)

you have a mysql account with that particular user identification? bastien

From: Nayyar Ahmed <nayyares@gmail.com> Reply-To: Nayyar Ahmed <nayyares@gmail.com> To: php-db@lists.php.net Subject: [PHP-DB] help newbies :) Date: Thu, 23 Dec 2004 20:54:23 +0500 Hello All, I am developing attendence mangement system, its my first application in PHP, I want to compaire the input text box value with table records the follwing is the code _____________index.htm_______________ .......... <form name = 'loginfrm' method = post action = "index.php" >

  <pre>    	</td>

</tr> <tr>

    <td width="100%" height="115"><html>

<body> <div style="mso-border-alt: solid #AAAAFF .75pt; width: 675; height: 234; border: 1.0pt solid #AAAAFF; padding: 6.0pt; background: #EEEEFF"> <table border="0" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#111111" width="100%" id="AutoNumber2">

    <tr>

      <td width="25%"><font size="4">User Name:</font></td>

      <td width="25%">

      <p><input name = "uname" type = "text" size="20"></p>

      </td>

      <td width="25%"><font size="4">&nbsp;&nbsp;&nbsp;&nbsp; Class:</font></td>

      <td width="25%"> <select name= "class">

      					 <option value = "BBA"> BBA</option>

      					 <option value = "BBA-IT"> BBA-IT</option>

      					 <option value = "BCS"> BCS</option>

      					 <option value = "B.Sc"> B.Sc</option>

      					 <option value = "MBA"> MBA</option>

      					 <option value = "MBA-IT"> MBA-IT</option>

      					 <option value = "MS-IT"> MS-IT</option>

      					 <option value = "MS-CS"> MS-CS</option>

      					 <option value = "Admin"> Admin</option>

      					</select> </td>

      <td width="25%"><font size="4">Password:</font></td>

      <td width="25%"><input name ="passwd" type = "password" size="20"> </td>

etc. etc. ....... _____________________________________________________ _________index.php_____________ <?php $db= mysql_connect("localhost","root","masood"); mysql_select_db("attendence",$db); $result= mysql_query("select uname,upasswd from user",$db); while ($myrow = mysql_fetch_array($result)) { if(($uname == $myrow["uname"]) && ($upasswd == $myrow["uname"])); { echo $myrow["uname"]; echo $myrow["upasswd"]; } } ?> </body> </html> this give me error no 13, with uname,upasswd undefined, please help me out, TIA -- Nayyar Ahmad Lecturer Faculty Of Computer Science, Institute Of Management Sciences, Hayat Abad Peshawar , Pakistan. Office : 92-091-9217404 , 9217452

Cell     :  92-0333-9139461

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