Re: SV: [PHP-DB] Assistance with if..elseif statement
| From: | Craig Hoffman | Date: | Mon, 17 Jan 2005 16:33:58 +0000 |
| Subject: | Re: SV: [PHP-DB] Assistance with if..elseif statement | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-38182@lists.php.net to get a copy of this message | ||
Thanks all - CH
On Jan 17, 2005, at 8:35 AM, Henrik Hornemann wrote:
Hi, } elseif ($_POST['route_photo'] = $_POST['oldimage']) Should probably be } elseif ($_POST['route_photo'] == $_POST['oldimage']) Regards Henrik Hornemann -----Oprindelig meddelelse----- Fra: Craig Hoffman [mailto:choffman@eclimb.net] Sendt: 17. januar 2005 15:22 Til: php-db@lists.php.net Emne: [PHP-DB] Assistance with if..elseif statement I have this block of code which checks to see if an image has been uploaded from an update form. Everything in the form works, except I can not get the the elseif statements to behave properly. See the comments below for explanation. Any help would be appreciated. $route_photo = $_FILES['image']['name']; // if no new image and no existing image put NULL in the DB if(empty($_FILES['image']['name']) && ($_POST['oldimage']) == ''){ $route_photo = 'NULL'; echo ("No image supplied.");// if new image put the new image name in the DB} elseif ($_POST['route_photo'] || $_FILES['image']['name']) { $route_photo = $_POST['route_photo']; echo ("The image has been replaced with$route_photo."); // If no new image update, use the old image} elseif ($_POST['route_photo'] = $_POST['oldimage']) { $route_photo = $_POST['oldimage']; echo("No new image supplied"); }-- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php