Re: if statement

Craig Hoffman wrote:

Hi There, I am trying to write an if statement to see if an array has any values in it and if it does do something. for example: $ticklist2 = array("'$values")

if (array_values(empty($ticklist2)))    {

empty() is used to check whether a var isset and is not null, "" or false - and it returns a boolean value not an array; php -r ' $a = null; $b = false; $c = ""; var_dump($a,$b,$c); if (empty($a)) { echo "\$a is empty.\n"; } if (empty($b)) { echo "\$b is empty.\n"; } if (empty($c)) { echo "\$c is empty.\n"; } ' array_values() expected an array as its argument. maybe it can auto-cast any var it receives to an array but I don't know (I never use it like that anyway.) what is does do return an array with an associative keys 'replaced' with numeric keys - come to think of it I don't use this function at all. any have a good use for the function, just out of interest? if you want to remove empty values: php -r ' $a = array("yeah", null, "", "yeah", "baby!"); var_dump($a,array_filter($a)); ' if you want to remove empty values and duplicates: php -r ' $a = array("yeah", null, "", "yeah", "baby!"); var_dump($a,array_unique(array_filter($a))); '

do something } else { do something else }

php -r ' $a = array( null, null ); var_dump($a); if ($a) { echo "\$a has items.\n"; } if ($aCnt = count($a)) { echo "\$a has {$aCnt} items.\n"; } $b = array(); if ($b) { echo "\$b has items.\n"; } if (empty($b)) { echo "\$b is empty.\n"; } $c = array("f" => "me"); if (!$c) { echo "\$c is empty items.\n"; } if (!empty($c)) { echo "\$b is empty.\n"; } '

I just can't get this to work. Any help would be great.

http://nl2.php.net/echo http://nl2.php.net/empty http://nl2.php.net/var_dump http://nl2.php.net/array http://nl2.php.net/array_unique http://nl2.php.net/array_filter

Thanks, Craig H.