RE: [PHP-DB] empty set query
| From: | Bastien Koert | Date: | Tue, 08 Feb 2005 18:32:49 +0000 |
| Subject: | RE: [PHP-DB] empty set query | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-38523@lists.php.net to get a copy of this message | ||
Every var should be set at the beggining of the script
$title = '';
$director = '';
then if there is no result, already has a value
bastien
From: "J. Connolly" <web@jozef.info> To: PHP list <php-db@lists.php.net> Subject: [PHP-DB] empty set query Date: Tue, 08 Feb 2005 13:22:56 -0500 I have a query which can result in an empty set/ no matching records. The code I have which returns a code is: $result = mysqli_query($link, $sql); while ($query = mysqli_fetch_array($result)){ $title = $query['title']; $director = $query['director']; echo "<table><tr><td>$title</td><td> $director</td></tr></table>\n";}If the resulting query is a empty set, which variable or item to I refence as null. I already triedif (!query) and (!$title)and neither of them work. I also tried if either of them are null. I don't need someone to give me a long explanation just a small bump as to what I should be referencing. In other words, what is it that I should reference? Should I just write a code that returns number of rows and use that? Jzf -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php