Re: Expiry Date ($date function)

Ron Piggott wrote:

That strtotime is a neat little command. With a bit more searching I found that this works: $expiry_date = strtotime("+21 days"); $expiry_date = date('Y-m-d', $expiry_date); echo $expiry_date; The computer couldn't cope with me doing it in just one line --- I got a parse error.

the computer coped when I did it on oneline, maybe you had a typo or something: echo date("Y-m-d", strtotime("+21 days")); sidenote: I use doublequotes here because its easier when testing in a linux shell....but unless you need string interpolation its better to use single quotes for your strings.

Ron ----- Original Message ----- From: Calvin Lough <calvinlough@gmail.com> To: Ron Piggott <ron.php@actsministries.org>; PHP DB <php-db@lists.php.net> Sent: Wednesday, March 02, 2005 10:50 AM Subject: Re: [PHP-DB] Expiry Date ($date function)

The strtotime function should work the best. $add_twentyone = strtotime("+21 days"); I dont know if that will work or not. I just found that method in the php doc and it looked interesting. Hopefully it will work for you. Calvin On Wed, 2 Mar 2005 04:41:04 -0500, Ron Piggott <ron.php@actsministries.org> wrote:

I figured out that the syntax below creates the date in the way it may

be

stored in a mySQL table: $todays_date=DATE('Y-m-d'); Is there any way to add 21 days to this as an expiry date? For example

if

the date was March 20th 2005 21 days would be in April --- is there any

way

of dealing with this? Ron -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php