RE: [PHP-DB] What wrong with my Query??
| From: | Gary Every | Date: | Fri, 25 Mar 2005 20:53:18 +0000 |
| Subject: | RE: [PHP-DB] What wrong with my Query?? | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-39040@lists.php.net to get a copy of this message | ||
Actually, your sql syntax is wrong. The SET keyword if for UPDATE not
INSERT
Use
$sql = "INSERT INTO mfadmin
(id,account,planlimit,name,email,password,lastlogin,datecreated,expiry,l
astip) VALUES
('','$accname_lc','$plans','$yourname','$email','$password','$datetoday'
,'$datetoday','$expirydate','123.123.123.123')";
Gary Every
Sr. UNIX Administrator
Ingram Entertainment Inc.
2 Ingram Blvd, La Vergne, TN 37089
"Pay It Forward!"
-----Original Message-----
From: HarryG [mailto:harry1980@gmail.com]
Sent: Thursday, March 24, 2005 11:27 PM
To: php-db@lists.php.net
Subject: [PHP-DB] What wrong with my Query??
What the hell is wrong with this MYSQL query?? PHP keeps giving me the
error message:
You have an error in your SQL syntax. Check the manual that corresponds
to your MySQL server version for the right syntax to use near
'limit=20000, name='test1', email='atest@test.com', password='t
$query = "INSERT INTO mfadmin SET id='', account='$accname_lc',
limit=$plans, name='$yourname', email='$email', password='$password',
lastlogin='$datetoday', datecreated='$datetoday',
expiry='$expirydate',
lastip=123.123.123.123";
This is my table structure
CREATE TABLE
admin (
id int(10) unsigned NOT NULL auto_increment,
account varchar(50) NOT NULL default '',
limit int(10) unsigned NOT NULL default '0',
name varchar(50) NOT NULL default '',
email varchar(50) NOT NULL default '',
password varchar(50) NOT NULL default '',
lastlogin varchar(50) NOT NULL default '',
datecreated varchar(50) NOT NULL default '',
expiry varchar(50) NOT NULL default '',
lastip varchar(50) NOT NULL default '',
PRIMARY KEY (id)
) TYPE=MyISAM;