RE: [PHP-DB] Question about COUNT(*)

Thanks Rory, This query solves the problem: SELECT client.client_name, IFNULL( COUNT( sales.sale_id ) , 0 ) AS total FROM CLIENT LEFT JOIN sales ON client.client_id = sales.client_id GROUP BY client.client_name ORDER BY total DESC Also thanks to Nandar and Prabhu, but MySQL does not recognize '*=' operator. You guys is very helpful, thanks again :) Erick Wellem <snip> You could also try something like this: SELECT client.name, IFNULL(COUNT(sales.sale_id), 0) AS total FROM client LEFT JOIN sales ON client.client_id = sales.client_id GROUP BY client.name ORDER BY total DESC The left join forces every record in the left table of the join (client) to be present in the result set whether or not there are matching entries in the right table (sales). The IFNULL takes care fo your count problem. </snip>