Re: Brain not working, help needed :-)

you can also do this to save room without having to create $varname: ${"id".$num} = "some text"; Jordan On Aug 29, 2005, at 12:10 AM, Micah Stevens wrote:

Hi Chris, You can use variable variables.. like this: $num = 2 $varname = "id".$num; $$varname = "id2 is stored here!"; It's in the docs in the variables section.. HTH, -Micah On Sunday 28 August 2005 11:45 pm, Chris Payne wrote:

Hi there everyone, I have the following code: while ($row = mysql_fetch_array($sql_result)) { $id = $row["id"]; $video_link = $row["video_link"]; $video_thumbnail = $row["video_thumbname"]; $video_title = $row["video_title"]; $video_description = $row["video_description"]; }; Now I’ll be shifting through my MySQL array 6 items at a time, what I’d LIKE to be able to do is store each item in a number string on each pass. In other words, the first loop would see $id being called something like $id1, the second pass in the loop it would be $id2 and so on. I THOUGHT I could do this by putting a $count ++ in the loop and then doing something like $id$count or something like $id.$count but neither worked, this may sound odd but I REALLY need to be able to do this so how can I name a string that has to contain the data from a row successively higher on each loop so that it doesn’t overwrite the data on the previous loop? I have 6 items on the page so I can hardcode <?=$id1?> for item 1 and <?=$id2?> for item 2 etc …. But with the layout of the page being able to do it THIS way would be MUCH better than having to set the table itself up to handle it. Any help on this (Probably very easy) but annoying problem would be REALLY appreciated ;-) Chris

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