RE: [PHP-DB] If syntax

think this is wrong ... as it gives unique alias even if the query is not executed .. rajesh On Sun, 2 Oct 2005, Bastien Koert wrote:

you need to check the num of rows returned, since the query always(if it works) returns true $result = mysql_query($query); if (($result)&&(mysql_num_rows($result)==1)) { echo "Alias already in use"; } else { echo "Unique alias"; mysql_close(); } Bastien

From: "Ron Piggott" <ron.php@actsministries.org> Reply-To: "Ron Piggott" <ron.php@actsministries.org> To: "PHP DB" <php-db@lists.php.net> Subject: [PHP-DB] If syntax Date: Sat, 1 Oct 2005 22:28:46 -0500 Take a look at my if ( ) syntax line below. I am wondering if I have it wrong in same way. What I am trying to achieve is if the alias the user enters is already found in the database I want the words "Alias already in use" to be shown on the screen; otherwise "Unique alias" to be shown on the screen. PRESENTLY alias already in use is what comes up all the time. Ron mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM tablename WHERE alias LIKE '$alias%'"; if (mysql_query($query)) { echo "Alias already in use"; } else { echo "Unique alias"; mysql_close(); } -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

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