Re: isset or ! isset what is my problem?

NULL != Not set. isset() tests to see if the variable exists. If your variable has a null value it is set, it DOES exist, it just has NULL for a value. You should test for a null value if that's what you want: if ($picture == null) Or perhaps the empty() function might be what you're looking for. -Micah On Monday 02 January 2006 7:54 pm, Ralph wrote: > I'm building a URL based on data extracted from mySQL and I want the > text space.gif used as my default value should the variable $picture > by NULL. > > The results of the code below kick back a value for $picture when it > is set in the database, but ignores the space.gif if the database > result is empty. > > If I flip the test from ! isset to isset then I get the space.gif for > each result. > > > I've had no luck searching out an answer. > > Thanks in advance. > > --------------The Code----------------------------- > <?php do { ?> > <img src="images/<?php > $picture=$row_rst_screenings['Picture']; > > if(! isset($picture)) { > $picture='space.gif'; > }else{ > $picture=$row_rst_screenings['Picture']; > } > > echo $picture; > > ?>"><br> > <p><span class="style2"><?php echo > $row_rst_screenings['Title']; ?></ > span><br /> > <span class="style3"><?php echo $row_rst_screenings['Director']; > ?></ > span></p> > <p class="style4"><?php echo $row_rst_screenings['Blurb']; > ?></p> > <p class="style3">Showtime: <?php echo $row_rst_screenings > ['ShowTime']; ?> <?php echo $row_rst_screenings['ShowDate']; > ?></p> > <p class="style3">Location: <?php echo $row_rst_screenings > ['Location']; ?></p> > > <?php } while ($row_rst_screenings = mysql_fetch_assoc > ($rst_screenings)); ?> > > ---------------END-----------------