Hi List,
I do not claim that this is bug, but it is not a nice feature either.
I do have following:
<?
/* db.php */
$db_server="127.0.0.1";
$db_user = ******
$db_pass = ******
$db_db = "bebbicell";
$db_account_server="127.0.0.1";
$db_account_user = ********
$db_account_pass = ********
$db_account_db = "asterisk";
//$level= error_reporting ( 0);
$bid=mysql_pconnect($db_server,$db_user,$db_pass);
//error_reporting ( $level);
mysql_select_db($db_db,$bid);
//$level= error_reporting ( 0);
$accid=mysql_pconnect($db_account_server,$db_account_user,$db_account_pass);
//error_reporting ( $level);
mysql_select_db($db_account_db, $accid);
?>
Note that databases here are totally unrelated. They are on the same machine only because i am developing. I want later to move 'asterisk' to a separate machine, but when i do this, i want just change $db*s, not any other code. Because on this, i want both $bid and $accid to be valid handles.
Currently it is not so. Both
$res = mysql_query($sql,$accid);
$err = mysql_error($accid);
will generate error
Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /var/www/bebbicell.ch/signup.php
Hmm... from the manual:
First, when connecting, the function would first try to find a
(persistent) link that's already open with the same host, username and
password. If one is found, an identifier for it will be returned instead
of opening a new connection.
That is, the database is not considered in determining a pre-existing
persistent connection.
So, if $db_user == $db_account_user and $db_pass == $db_account_pass
then $bid == $accid.
That said though what you have above should work since multiple calls to
mysql_pconnect with the same parameters should just return the original
handle.
Perhaps (and assuming the connection info is identical) $db_user doesn't
have access to $db_account_db to run whatever $sql query you're running?
That error doesn't seem right for that, but that's the only thing I can
think of.
-philip