Re: SELECT date query

From: Date: Sat, 07 Oct 2006 04:49:36 +0000
Subject: Re: SELECT date query
References: 1  Groups: php.db 
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Hi Ron I've made the assumption that if today is Wednesday, you still want next Wednesday. Try this: $offset = array(3,2,1,7,6,5,4); $date = explode("-", date("Y-n-j")); $ToDay = DayOfWeek($date[0], $date[1], $date[2]); $NextWed = date("Y-n-j", time() + ($offset[$ToDay] * 24 * 60 * 60)); // Returns a digit in range 0-6. 0 = Sunday, 6 = Saturday function DayOfWeek($Year, $Month, $Day) { $t = array(0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4); $Year -= $Month < 3; return ($Year + ($Year / 4) - ($Year / 100) + ($Year / 400) + $t[$Month - 1] + $Day) % 7; } Niel

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