RE: [PHP-DB] Arrays from forms....

From: Date: Fri, 01 Dec 2006 04:38:31 +0000
Subject: RE: [PHP-DB] Arrays from forms....
References: 1 2 3 4 5 6 7 8 9 10  Groups: php.db 
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OK.. I am a moron.. Forgot that I had changed the name of the field in the form, and got sidetracked and didn't change it in the php... But, still not working correctly. Here is the output: Array -- Array -- Array from: <?php include "db.inc.back.php"; foreach ($_FILES["pictures"]["error"] as $key => $error) { if ($error == UPLOAD_ERR_OK) { echo "$error_codes[$error]"; move_uploaded_file( $_FILES["pictures"]["tmp_name"][$key], "bikeimages/" .$_FILES["pictures"]["name"][$key] ) or die("Problems with upload"); ${"image".($key+1)} = $_FILES['pictures']['name']; } } $make = $_POST['make']; $model = $_POST['model']; $year = $_POST['year']; $color = $_POST['color']; $description = $_POST['description']; //$image1 = $_POST['image1']; //$image2 = $_POST['image2']; //$image3 = $_POST['image3']; $status = $_POST['status']; echo "$image1 -- $image2 -- $image3"; /* $query = "INSERT INTO inventory (make, model, year, color, description, image1, image2, image3, status) VALUES ('$make', '$model', '$year', '$color', '$description', '$image1', '$image2', '$image3', '$status');"; $result = mysql_db_query("$db", $query) or displayErrorQuery ($query); echo "<meta http-equiv='refresh' content='0;URL=inventorylist.php'>"; exit; */ ?>

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