Re: echo

elk dolk wrote:

thanks to Chris and Dimiter, I think I am close but still the problem is not solved, when I add echo "<img src='/album/img/".$row["photoFileName"]."' /> to the code as it was sugested by Dimiter there is parse Error : PHP Parse error: syntax error, unexpected $end in C:\Inetpub\wwwroot\album\show.php on line 44 line 44 is end of the code just after </html> what does it mean? probably you don't have a semi colon at the end of your echo line....

nor is there and end double quote.

I am storing just the name of photos in the database and the photos are in /img folder ,and there is no permissions issue. My testing server is IIS And the path would be something like this : Inetpub\wwwroot\album\img as I am running out of time! could someone complete this code just with one echo and img src so that I can retrive my photos ?

MySQL columns : photoID=seq number photoFileName=name of my photo like 3sw.jpg title=title description=short description -----------------------------------------------------------------

<body> <?php $link = mysql_connect('localhost', 'root', 'pw'); if (!$link) {

             die('Not connected : ' . mysql_error());

}

              echo 'connected!';

$db_selected = mysql_select_db('album', $link); if (!$db_selected) {

                    die ('Can\'t use foo : ' . mysql_error());

} $query = "SELECT * FROM photo"; $result=mysql_query($query); while ($row = mysql_fetch_array($result)) { echo "<img src='/album/img/".$row["photoFileName"]."' /> } mysql_free_result($result); ?> </body>

</html>               

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