RE: [PHP-DB] width& height
| From: | Bastien Koert | Date: | Fri, 30 Mar 2007 13:09:41 +0000 |
| Subject: | RE: [PHP-DB] width& height | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-43381@lists.php.net to get a copy of this message | ||
you need to escape double quotes in an echo if you use double quotes as the wrapper.
bastien
From: elk dolk <elkdolk@yahoo.com> To: "php-db@lists.php.net" <php-db@lists.php.net> Subject: [PHP-DB] width& height Date: Fri, 30 Mar 2007 04:31:52 -0700 (PDT) it might be a stupid question but I think it would be the last one! I am trying to define the height and width of picture in the following line: "<img src='/album/img/".$photoFileName[2]." / >"; ?></td> when I put it like this: <table width="50%" border="0" cellspacing="3" cellpadding="0"> <tr>_________________________________________________________________ Your Space. Your Friends. Your Stories. Share your world with Windows Live Spaces. http://spaces.live.com/?mkt=en-ca<td width="90" height="70"><?php echo "<img src='/album/img/".$photoFileName[2]." width="90" height="70" border='0' / "; ?></td></tr> <tr><td width="90" height="70"> </td> <td width="90" height="70"> </td></tr> </table> <p> </p> <p> I have this error: PHP Parse error: syntax error, unexpected T_LNUMBER, expecting ',' or ';' in C:\Inetpub\wwwroot\album\2dimArray2.php on line 44 please comment! --------------------------------- Bored stiff? Loosen up... Download and play hundreds of games for free on Yahoo! Games.