Re: I want to remove the last comma

JSON does the trick for you (www.json.org), and PHP's glob() gets rid of your readdir() overhead (you'll need PHP 5.2 or later for this): $path = "/path/to/images/"; $images = glob($path . "{*.jpg,*.gif,*.png}", GLOB_BRACE); for ($i = 0; $i < sizeof($images); $i++) $images[$i] = array($images[$i], $path . $images[$i]); $js_output = "var tinyMCEImageList = " . json_encode($images) . ";"; I'd also save myself the overhead of repeating the same path $i times in my array, and instead just create a JS object: $path = "/path/to/images/"; $js_output = "var tinyMCEImageList = " . json_encode(array("path" => $path, "images" => glob($path . "{*.jpg,*.gif,*.png}", GLOB_BRACE))) . ";"; You can append the path client side after he page is parsed. Apart from that, echo-ing javascript in your php code is never really a good idea when it comes to louse coupling of your web applications. If that's no consideration for you - party on. Again, this is not a PHP-DB question, you should subscribe to the PHP-GENERAL (or-whatever-it's-called) list. On Tue, Aug 12, 2008 at 9:27 PM, A. Joseph <joefazee@gmail.com> wrote: > This the script > $dir = "images"; > $d = opendir($dir); > $out = " > var tinyMCEImageList = new Array(\n"; > while(false != ($entry = readdir($d))) { > if(preg_match("/(.jpg|.gif|.png)$/", $entry) != false) { > $out .= "['{$entry}', '{$dir}/{$entry}'],\n"; > } > > } > $out .= ");\n"; > > This the out put > > var tinyMCEImageList = new Array( > ['1_h_1.gif', 'images/1_h_1.gif'], > ['1_h_2.gif', 'images/1_h_2.gif'], > ['rss_2.jpg', 'images/rss_2.jpg'], > ['spacer.gif', 'images/spacer.gif'], # I want to remove this comma > ); > > if the last element (['spacer.gif', 'images/spacer.gif'],) contain comma, > javascript will return error, so i want to remove it. >