İlgi: [PHP-DB] mysql_numrows

query in error $blog_activity_result , $number_of_entries=mysql_numrows($blog_activity_result); this line before echo mysql_error(); add , you see error . after edit your error :)) 2008/10/12, Roberto Carlos García Luís <legnakarlos@gmail.com>: > You can use, $number_of_entries=@mysql_numrows($blog_activity_result); > > with @ you silence the error in the display. > > Robert C. > > > El 12/10/2008, a las 01:19 p.m., Ron Piggott escribió: > >> When I do the following command: >> >> $number_of_entries=mysql_numrows($blog_activity_result); >> >> and there are no rows I get an error (Warning: mysql_numrows(): >> supplied >> argument is not a valid MySQL result resource in ...) >> >> When that happens I want to display a greeting to invite the user to >> engage in the community blog I am creating. How can I make my own >> greeting, instead of displaying the error mySQL is giving me? >> >> Ron >> >> >> -- >> PHP Database Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php >> > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- şahabettin akca // saho