Copying Data From One Table To Another Table
| From: | Alice Wei | Date: | Thu, 13 Nov 2008 23:30:51 +0000 |
| Subject: | Copying Data From One Table To Another Table | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-45630@lists.php.net to get a copy of this message | ||
Hi,
I am trying to accomplish a task of which I have to copy the data from one table to another. The
problem is that whenever I tried to perform the action of copying the data through this method,
although the data gets copied, it performs reiterative copying that causes my program and my server
to crash.
Here is the code snippet:
#Empty Temporary Array
$tmpHolder = array();
$tmpHolder2 = array();
#Loop through parts list
foreach ($stringChunk1 As $part) {
#Create a single statement and stuff it in your tmp array
$tmpHolder[]="incidence.name LIKE '%{$part}'";
}
foreach ($stringChunk2 As $part2) {
#Create a single statement and stuff it in your tmp array
$tmpHolder2[]="regions.name LIKE '%{$part2}'";
}
#Join all the parts together, placing an OR between each element
$string3= join(' OR ', $tmpHolder);
$string2= join(' OR ', $tmpHolder2);
$total=$count_chunk1 * $count_chunk2;
//Entry a New Query Entry into scenarios table
$query3="INSERT INTO scenarios VALUES('$scenario_name')";
$result3=mssql_query($query3) or die ("The query has failed");
#Search for the Regions and Incidence ID
$query_both="SELECT incidence.ID,regions.ID from incidence,regions WHERE ($string3)AND
($string2)";
$result_both=mssql_query($query_both) or die ("The query has failed");
while($row_both = mssql_fetch_array($result_both)) {
$incidence_id= $row_both[0];
$region_id= $row_both[1];
//Enter entry into scenario elements table
// $query14="INSERT INTO
scenario_elements(region_id,incidence_id,market,number_sales,number_defer,customer_satisfaction)
// SELECT region_id,incidence_id,market,number_sales,number_defer,customer_satisfaction FROM
scenario_elements_2,regions,incidence WHERE $string2 AND $string3";
// $result14=mssql_query($query14) or die ("The query has failed");
I have to comment out the code snippet above because it creates something like 30000 entries to the
database. Could anyone please tell me if this is the error I have from my PHP, or is it from my SQL
statement? How would I go about fixing this issue?
Thanks in advance.
Alice
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