Re: how does one bind a gui representation and a container object.
| From: | Fred Silsbee | Date: | Thu, 08 Jan 2009 23:12:18 +0000 |
| Subject: | Re: how does one bind a gui representation and a container object. | ||
| Groups: | php.db php.general | ||
| Request: | Send a blank email to php-db+get-45874@lists.php.net to get a copy of this message | ||
--- On Thu, 1/8/09, Fred Silsbee <fredsilsbee@yahoo.com> wrote:
> From: Fred Silsbee <fredsilsbee@yahoo.com>
> Subject: how does one bind a gui representation and a container object.
> To: php-db@lists.php.net, php-general@lists.php.net
> Date: Thursday, January 8, 2009, 10:41 PM
> I have a Qt 4.4 C++ SQL offline program that displays an SQL
> table.
>
> When I change a row-column cell, the change is instantly
> reflected in the database. Under Qt 4.4 I use:
>
> QSqlTableModel
>
> How does one do this in PHP for online use.
>
> I've done this under C#.NET VS2008 using
> "binding" between a gui representation and the
> container object.
error I get under Firefox 3.0.5 under Fedora 9 PHP 5.2.6
Unknown Renderer driver. Please specify an existing driver.
Code:
<?php
require 'Structures/DataGrid.php';
// Instantiate the DataGrid
$datagrid =& new Structures_DataGrid();
// Setup your database connection
$options = array('dsn' => 'mysql://landon4:pwpwpwpwpw@localhost/landonx');
// Bind a basic SQL statement as datasource
$test = $datagrid->bind('SELECT * FROM log_book', $options);
// Print binding error if any
if (PEAR::isError($test)) {
echo $test->getMessage();
}
// Print the DataGrid with the default renderer (HTML Table)
$test = $datagrid->render(Structures_DataGrid_Renderer_HTMLTable);
// Print rendering error if any
if (PEAR::isError($test)) {
echo $test->getMessage();
}
?>