Re: Re: Problems with INNER JOIN

Try that query in console or use Navicat/phpMyAdmin to run it. Remove the HAVING part to see if the SELECT returns what you need. Terion Miller napsal(a):

Thanks Martin, oddly enough that still doesn't pull any results, it won't even print the variables if I try to list them to see, I know my db connection is good checked that, and can do really simple queries, would something be preventing a JOIN from working? When I Reveal my variables this query snippet:

    $sql = "SELECT admin.AdminID, workorders.WorkOrderID

FROM admin INNER JOIN workorders ON admin.AdminID=workorders.AdminID HAVING admin.username='".$_SESSION['user']."' ";

      $result2 = mysql_query ($sql);
      $row2 = mysql_fetch_assoc ($result2);
      $Total = ceil(mysql_num_rows($result2)/$PerPage);

Returns this: $sql"SELECT admin.AdminID, workorders.WorkOrderID FROM admin INNER JOIN workorders ON admin.AdminID=workorders.AdminID HAVING admin.username='tmiller' "$result2""$row2"" Terion On Thu, Jan 29, 2009 at 11:56 AM, Martin Zvarík <mzvarik@gmail.com> wrote:

This will work: $sql = " SELECT admin.AdminID, workorders.WHAT_YOU_WANT FROM admin INNER JOIN workorders ON admin.AdminID=workorders.AdminID HAVING admin.username='".$_SESSION['user']."' "; Terion Miller napsal(a): Hi Everyone! I am having problems getting an INNER JOIN to work and need

    
some tips trouble shooting where the problem may be.

What I'm trying to do is match up AdminID's from two tables and display only that users orders, sounds simple enough right...but I can't get it to return the AdminID... My Query: $sql =

    "SELECT admin.AdminID , workorders.AdminID
        FROM admin
            INNER JOIN
        workorders ON
         (admin.AdminID=workorders.AdminID)
        WHERE admin.UserName =   '".$_SESSION['user']."' ";

     $result = mysql_query ($sql);
     $row = mysql_fetch_assoc ($result);
     $Total = ceil(mysql_num_rows($result)/$PerPage);

Thanks for any tips on how else I can accomplish this... Terion

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