Re: Retrieving Image Location in MySQL
| From: | Sashikanth Gurram | Date: | Fri, 06 Mar 2009 17:23:31 +0000 |
| Subject: | Re: Retrieving Image Location in MySQL | ||
| References: | 1 2 3 4 5 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-46038@lists.php.net to get a copy of this message | ||
Dear all,
I have been trying to retrieve the location of a image from database and display the image in the browser using PHP. I have written a sort of code for the purpose. All I am getting in my browser after using the code is a long set of ASCII characters with the following warning
*Warning*: Cannot modify header information - headers already sent by (output started at C:\wamp\www\mysqli.php:65) in *C:\wamp\www\mysqli.php* on line *237
*
I am herewith attaching my code. If anyone can point out the error or give some kind of advice that would be really great. The location of the image is stored in a table by the name IMAGE under the column name Location and here in the code, the location is retrieved under the varibale name $Location.
thanks,
Sashi
/<html>
<body>
<form action="mysqli.php" method="post">
<br>
<div align="center">
Building Name:<select name="name">
<option value=""> Select a Building</option>
<option value="Agnew Hall">Agnew Hall</option>
<option value="Rector Field House">Rector Field House</option>
<option value="Richard B. Talbot Educational Resources Center">Richard B. Talbot Educational Resources Center</option>
<option value="Robeson Hall">Robeson Hall</option>
<option value="Sandy Hall">Sandy Hall</option>
<option value="Saunders hall">Saunders hall</option>
<option value="Seitz Hall">Seitz Hall</option>
<option value="Shanks Hall">Shanks Hall</option>
<option value="Shultz Hall">Shultz Hall</option>
<option value="Skelton Conference Center">Skelton Conference Center</option>
<option value="Williams Hall">Williams Hall</option>
<option value="Women's Softball Field">Women's Softball Field</option>
<option value="Wright House">Wright House</option>
</select>
</div>
<input type="submit" /></form> <img src="mysqli.php?"> <?php // Connects to your Database $host="*******"; $user="*****"; $password="******"; $dbname="*******"; $cxn=mysqli_connect($host, $user, $password, $dbname) ; if (!$cxn=mysqli_connect($host, $user, $password, $dbname)) {
$error=mysqli_error($cxn);
echo "$error";
die();
}
else
{
echo "Connection established successfully";} //Define the variables for Day and Month $Today=date("l"); $Month=date("F"); $build=$_POST["name"]; $low_speed=2.5; $high_speed=4; $hour=date("G"); $minute=date("i"); if ($minute>=00 && $minute<=14) {
$minute=00;} elseif ($minute>=15 && $minute<=29) {
$minute=15;} elseif ($minute>=30 && $minute<=44) {
$minute=30;} else {
$minute=45;} $times="$hour:$minute"; $sql="SELECT buildingname, parking_lot_name, empty_spaces, distance, round(distance/($low_speed*60),1) AS low_time, round(distance/($high_speed*60),1) AS high_time, Location FROM buildings, buildings_lots, parkinglots, occupancy2, Image where (buildings.buildingcode=occupancy2.building AND buildings.buildingcode=buildings_lots.building_code AND parkinglots.parking_lot_code=buildings_lots.parking_lot_code AND parkinglots.parking_lot_code=occupancy2.parking_lot AND Buildings.BuildingCode=Image.BuildingCode) AND buildingname='$build' AND month='$Month' AND day='$Today' AND Time='$times'"; $data = mysqli_query($cxn,$sql); if (!$data=mysqli_query($cxn,$sql)) {
$error=mysqli_error($cxn);
echo "$error";
die();
}
else
{
echo "<br>";
echo "Query sent successfully";
}
echo "<br>";
echo "<h1> PARKING LOT INFORMATION <h1>";
echo "<table border='1' cellspacing='5' cellpadding='2'>";
echo "<tr>\n
<th>Building</th>\n
<th>Parking Lot</th>\n
<th>Estimated Number of Empty Spaces</th>\n
<th>Distance (Feet)</th>\n
<th>Estimated walking time to the building</th>\n
</tr>\n";
while ($row=mysqli_fetch_array($data))
{
extract($row);$building = $row[0];
$parking_lot = $row[1];
$Number_of_Empty_Spaces = $row[2];
$Distance = $row[3];
$time_l = $row[4];
$time_h=$row[5];
$location=$row[6]; echo "<tr>\n
<td>$building</td>\n
<td>$parking_lot</td>\n <td>$Number_of_Empty_Spaces</td>\n
<td>$Distance</td>\n
<td>$time_h - $time_l mins</td>\n
<td>$location</td>\n
</tr>\n";} echo "</table>\n"; $err=1; if ($img = file_get_contents($location, FILE_BINARY)) { if ($img = imagecreatefromstring($img)) $err = 0; } if ($err) { header('Content-Type: text/html'); echo '<html><body><p style="font-size:9px">Error getting image...</p></body></html>'; } else { header('Content-Type: image/jpeg'); imagejpeg($img); imagedestroy($img); } ?> </body> </html>/ Sashikanth Gurram wrote:
Hello guys, Thanks to you all for your kind replies. I will try the steps and get back to you if I encounter more problems. Thanks, Sashi Fortuno, Adam wrote:-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Sashikanth Gurram Graduate Research Assistant Department of Civil and Environmental Engineering Virginia Tech Blacksburg, VA 24060, USAMatya, Ha, ha, ha! Thank you good friend. I did say I didn't try the code :-) AF> Please note, I haven't tried this. It just seems plausible. I apologize if I confused anyone. I just meant to show how the parameter could help retrieve a picture. I wasn't too concerned with the particulars. Hopefully the concept is sound. If not, please do flame my note so no one attempts it. Be Well, A- -----Original Message----- From: Mattyasovszky Janos [mailto:mail@matya.hu] Sent: Monday, March 02, 2009 9:29 AM To: php-db@lists.php.net Subject: Re: [PHP-DB] Retrieving Image Location in MySQL Fortuno, Adam írta:Sorry, but this won't work, since you don't map the value of the escaped $value to the %s, lets say with sprintf()... Regards, Matya//Write a query to pull out the picture's path $sql = "SELECT path FROM Image WHERE ID = %s"; mysql_real_escape_string($value);