Re: PHP and table/view names with '$'

Sorry Mark, It's early in the morning... Neil is right. It's a PHP error you're getting after all, not a SQL Server error. And yes, this is by design: double quotes allow for variable insertion/substitution " ". Single quotes don't ' '. However, if you don't want the $ to be interpreted within the double quotes, you should be able to prevent this by using the backslash \ character. So, we get: $name = "Yves";

$name2 = "$name Sucaet";    // "Yves Sucaet"
$name3 = '$name Sucaet';    // "$name Sucaet"
$name4 = "\$name Sucaet";    // "$name Sucaet"

hth, Yves

----- Original Message ----- From: <N.A.Morgan@bton.ac.uk> To: "Mark Casson" <confused@icube.co.uk>; <php-db@lists.php.net> Sent: Thursday, April 23, 2009 5:25 AM Subject: RE: [PHP-DB] PHP and table/view names with '$' I find that using single quotes rather than double quotes prevents variable substitution. I don't know if this is an undocumented feature, as the documentation says that both have the same functionality. Regards, Neil -----Original Message----- From: Mark Casson [mailto:confused@icube.co.uk] Sent: 23 April 2009 11:04 To: php-db@lists.php.net Subject: [PHP-DB] PHP and table/view names with '$' Hi, I am trying to access some of the v$ views using php on iis, with admin privileges. However, using: $stmt = OCIParse($conn, "SELECT * FROM v$sql"); gives me this error: PHP Notice: undefined variable: sql . . . Is there a way around this? Thanks Mark -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php