Displaying Password
| From: | Karl DeSaulniers | Date: | Tue, 22 Dec 2009 04:18:30 +0000 |
| Subject: | Displaying Password | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-46725@lists.php.net to get a copy of this message | ||
Hello List,
Hope your all ready for the Holidays, I know I am. :)
I have a situation where I want to display a users password as bullets instead of the actual password characters once read from the database.
I feel there is a better way than what I am doing. I am trying str_replace() with a for loop to loop throuth how many characters and replace each with a bullet when displaying.
Like this:
$replace_count = strlen($UserPassword);
for ($i=0; $i < strlen($UserPassword); $i++) {
$UserPassword = str_replace('a', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('b', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('c', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('d', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('e', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('f', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('g', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('h', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('i', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('j', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('k', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('l', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('m', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('n', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('o', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('p', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('q', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('r', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('s', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('t', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('u', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('v', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('w', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('x', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('y', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('z', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('1', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('2', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('3', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('4', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('5', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('6', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('7', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('8', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('9', '•', $UserPassword, &$replace_count);
$UserPassword .= str_replace('0', '•', $UserPassword, &$replace_count);
} //hide pasword
But I keep getting a paramiters error for str_replace.
Warning: Wrong parameter count for str_replace() in blah, blah, blah
Doesn't strlen return a number value?
Thanks in advance.
Karl DeSaulniers
Design Drumm
http://designdrumm.com