Re: PHP Objects and SQL Results

Thanks for the code Eric, it seems to loosely provide the functionality that I'm after. Just out of interest though, is there no other way to find the next result row in an object apart from dumping it into an array? Thanks, Paul Eric Lee wrote:

On Sat, Feb 13, 2010 at 3:26 AM, Paul <devineman@msn.com> wrote:

Hi all, I'm currently having a problem correctly formatting a table within a while loop. I'm using an object to store the results of a query, and using the while to iterate through it each row to produce the output: $query = "SELECT * FROM foo WHERE UserID = " .$uID . " ORDER BY bar"; $result = mysql_query($query); while($obj = mysql_fetch_object($result)) {

       $obj->bar;

} To properly format the table, I need to check the value of bar in the next iteration of the object (but have to do it on the current one). Using an array, I would do: next($obj); if($obj["bar"] == "something") {

       //do things

} prev($obj); Is there an equivalent to object? I've tried the above method, but nothing happens. I've also tried type casting it to an array, without success. Is there anyway to iterate through this?

Paul Is this the one you want ? $sql = 'select id, name from test'; $result = mysql_query($sql); $rows = array(); $row = null; while ($row = mysql_fetch_object($result)) {

    $rows[] = $row;

} reset($rows); for ($i = 0, $c = sizeof($rows) - 1; $i < $c; $i++) {

    next($rows);
    if (current($rows)->name)
    {
        // something to do
    }
    prev($rows);

    echo current($rows)->id, ' ', current($rows)->name, "\n";

    next($rows);

} if (current($rows)) {

    echo current($rows)->id, ' ', current($rows)->name, "\n";

} Regards, Eric,

Thanks, Paul -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php