Re: Re: Dynamic dropdown: where am I wrong?
| From: | Karl DeSaulniers | Date: | Wed, 25 May 2011 16:52:20 +0000 |
| Subject: | Re: Re: Dynamic dropdown: where am I wrong? | ||
| References: | 1 2 3 4 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-47808@lists.php.net to get a copy of this message | ||
Hi Fahim,
A quick google search and I found this.
http://groups.google.com/group/jquery-en/browse_thread/thread/203077d18a0b9823
Hopefully some other PHP programers can find use of it too.
If you have any more jQuery questions though, go to their forum, they have plenty.
jquery.com
Or email me directly and I'll try to help what I can. :)
Best,
Karl
On May 25, 2011, at 5:04 AM, Fahim Mohammad wrote:
Thanks Karl I am trying my hands on that. Thanks again fahim On Tue, May 24, 2011 at 11:55 PM, Karl DeSaulniers <karl@designdrumm.com> wrote: You could try using Ajax to get the field values from your database. And you wouldn't have to refresh the page. jQuery ajax does a nice job of this. HTH, Karl On May 24, 2011, at 10:27 PM, Jim Giner wrote: not an expert but from some things that I've done... When you handle the selection use JS and set a hidden field on your form wiht the choice. Do the same with your second dropdown and then let them click on a 'submit' <input> "Fahim Mohammad" <fahim.md@gmail.com> wrote in message news:BANLkTim47cjrUsXYz=t-Yfhaoz_iUntesA@mail.gmail.com... Hi Php users, I have a form that has two (has more but for sake of brevity I am assuming it to be two) dropdown menu. menu 1: select organism. menu 2: select genome. This menu depends on the selected value in the first menu. It query into database and populate the result in this menu. Once both are selected, I want a submit button that takes me to another page where I can process these values to perform some specific task on the database. I am using the following form tag <form name="theForm" method="get" enctype="multipart/form-data" action = 'processForm.php' > I have the following problem now: 1. If I keep the action value in the form tag above, after selecting the first option it direct me to the second page and I am not able to select the seconf option in the form. 2. If I remove the action value above then I can not submit the form as intended. 3. If I remove the "onChange="autoSubmit();"" from select tag then I am not able to pass the selected value in first option to mysql to get the result. I think I reached a place from where it is not possible for me to proceed ahead. I may need to change something which I am not aware of. Help needed. Thanks [php] <?php include'login.php'; $conn = mysql_connect($db_hostname, $db_username, $db_password ); $db = mysql_select_db('rugit',$conn); if (!$db) die("Unable to connect to MySQL: " . mysql_error()); ?> <?php $organism = $genomeVer = null; //declare vars if(isset($_GET["organism"]) && is_string($_GET["organism"])) { $organism = $_GET["organism"]; } if(isset($_GET["genomeVer"]) && is_string($_GET["genomeVer"])) { $genomeVer = $_GET["genomeVer"]; } ?> <script language="JavaScript"> function autoSubmit() { var formObject = document.forms['theForm']; formObject.submit(); } </script> <!-- Form tag --> <form name="theForm" method="get" enctype="multipart/form-data" > <!-- Option 1: Select the organism --> <select name="organism" onChange="autoSubmit();">Karl DeSaulniers Design Drumm http://designdrumm.com<option value="null">Select Organism</option> <option value= "human" <?php if(strcmp($organism, "human") == 0) echo" selected"; ?>>human</option><option value= "mouse" <?php if(strcmp($organism, "mouse") == 0) echo" selected"; ?>>mouse</option><option value= "rat" <?php if(strcmp($organism,"rat") == 0) echo "selected"; ?>>rat</option> </select> <br></br> <!--Option 2: select the genome --> <?php//POPULATE DROP DOWN MENU FOR Genome version corresponding to agiven organism$sql = "SELECT genomeVer FROM organismGenomeVer WHERE organism =\"$organism\"";$result = mysql_query($sql,$conn);?><br> <select name="genomeVer" onChange="autoSubmit();"> <option value="null">genomeVer</option><?phpwhile($row = mysql_fetch_array($result)) { echo ("<option value=\"$row[0]\" " . ($genomeVer ==$row["0"] ? " selected" : "") . ">$row[0]</option>");} mysql_free_result($result); echo"</select>";?> <!-- Submit button --> <br></br> <input type="submit" value="submit" class="html-text-box"> </form> [/php] --Fahim --PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Karl DeSaulniers Design Drumm http://designdrumm.com --PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php --Fahim Mohammad Bioinforformatics Lab University of Louisville Louisville, KY, USA Ph: +1-502-409-1167