Re: Re: Database Problems

On Sun, Jun 17, 2012 at 10:21 PM, Jim Giner <jim.giner@albanyhandball.com> wrote: > > "Ethan Rosenberg" <ethros@earthlink.net> wrote in message > news:0M5S00MGD2BH7C60@mta1.srv.hcvlny.cv.net... >> At 03:30 PM 6/17/2012, Jim Giner wrote: >>>"Ethan Rosenberg" <ethros@earthlink.net> wrote in message >>>news:0M5R005QYZRNMC40@mta6.srv.hcvlny.cv.net... >>> > Dear List - >>> > >>> >>> > >>> > The same query in a PHP program will only give me results for MedRec >>> > 10003 >>> > >>> >>>why the "where 1" clause?  Do you know what that is for? >> ================= >> Dear Jim >> >> Thanks >> >> As I understand, to enable me to concatenate phases to construct a query.. >> >> The query does work in MySQL fro the terminal. >> >> Ethan >> > > I don't think so.  All it does is return one record.  The where clause > defines what you want returned.  A '1' returns one record, the first one. > #10003 > > I wonder why you think "where 1" enables concatenation??  A query (IN SIMPLE > TERMS PEOPLE) is simply a SELECT ion of fields from a group of tables,with a > WHERE clause to define the criteria to limit the rows, and an ORDER BY to > sort the result set.  More complex queries can include GROUP BY when you are > including summary operators such as SUM(fldname) or MAX(fldname), or a JOIN > clause, or a host of other clauses that make sql so powerful.  In your case > I think you copied a sample query that (they always seem to be displayed > with a 'where 1' clause) and left the "1" on it.  To summarzie: > > SELECT a.fld1, a.fld2,b.fld1 from table1 as a, table2 as b WHERE a.key >100 > and a.key = b.key ORDER BY a.fld1 > > I"m no expert, but hopefully this makes it a little less complex for you. > Right, Why would WHERE 1 return only 1 record? That makes no sense and, no offense, it sounds like you really don't know where you're talking about. WHERE 1 is just a useless statement, but in his case makes it easier to concatenate multiple "AND ..." statements. As to the original problem, I guess that there might be something wrong with your code later on that parses the result? Did you try to use echo mysqli_num_rows($result1), just after the query to see how many rows it returned? - Matijn