Re: mysql query

From: Date: Wed, 21 Aug 2013 23:52:30 +0000
Subject: Re: mysql query
References: 1  Groups: php.db 
Request: Send a blank email to php-db+get-48785@lists.php.net to get a copy of this message
1) What is the error message? 2) This has an error:
values ('$upc', $qnt,'$mnf','$itm', odrpt, 0, $stk)
Missing '$' in front of 'odrpt'. Toby On 8/22/2013 12:48 AM, Ethan Rosenberg wrote:
Dear List - I can't figure this out.... mysql> describe Inventory; +-------------+-------------+------+-----+---------+-------+
| Field       | Type        | Null | Key | Default | Extra |
+-------------+-------------+------+-----+---------+-------+
| UPC         | varchar(14) | YES  |     | NULL |       |
| quant       | int(5)      | NO   |     | NULL |       |
| manuf       | varchar(20) | YES  |     | NULL |       |
| item        | varchar(50) | YES  |     | NULL |       |
| orderpt     | tinyint(4)  | NO   |     | NULL |       |
| ordrpt_flag | tinyint(3)  | YES  |     | NULL |       |
| stock       | int(3)      | YES  |     | NULL |       |
+-------------+-------------+------+-----+---------+-------+ Here are code snippets -
                          $upc   = $_SESSION['UPC'];
                          $qnt   = $_POST['quant'];
                          $mnf   = $_POST['manuf'];
                          $itm   = $_POST['item'];
                          $odrpt = $_POST['oderpt'];
                          $opf   = $_POST['ordrpt_flag'];
                          $stk    = $_POST['stock'];
                          $sql2 = "insert into Inventory (UPC, quant, manuf, item, orderpt, ordrpt_flag, stock)"
                                ."values ('$upc', $qnt,'$mnf','$itm', odrpt, 0, $stk)";
                          $result2 = mysqli_query(cxn, $sql2);
                          echo '$sql2<br />';
                          print_r($sql2);
                          echo "<br />$upc $qnt $mnf $itm $odrpt $opf $stk<kbr />";
                          if (!$result2)
                                die('Could not enter data: ' . mysqli_error());
The mysql query fails. I cannot figure out why. It works from the command line. TIA Ethan


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