Re: Newbie Question $2

On 6/18/2014 12:31 AM, Ethan Rosenberg, PhD wrote:

On 06/17/2014 12:02 PM, onatawahtaw@yahoo.ca wrote:

Hi Ethan, Here are some things to clean up your code: Your line: $phn = $_POST[phone]; should use quotations as follows: $phn = $_POST['phone']; Your line: $sql1 ='select Lname, Fname from Customers where Phone = $Phn '; Should use double quotes if you need the variable to be interpreted: $sql1 ="select Lname, Fname from Customers where Phone = $Phn "; Lastly, as people have mentioned PDO is probably the best way to go. Try connecting to your database with PDO. Look on Google for "PDO prepared statements" and use those instead of the mysql escape string method. Hope this helps, -Kevin Sent from Yahoo Mail on Android

IT WORKS!!! Here is the code - <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <html> <?php $bla = 1; ?>

     <head>
     </head>
         <body>
             <div align="center">
             <form method="post">
             <input type='text' name=phone></input>
             <input type='submit'>
             <br /><br /><br />
             </form>
             </div>

<?php

             error_reporting(-1);
             require '/home/ethan/PHP/ethan.inc';
             $db = "Store";
             $cxn = mysqli_connect($host,$user,$password,$db);

             $phn = $_POST[phone];
             $phn = (string)$phn;
             $dsh = '-';
             $Phn =

$phn[0].$phn[1].$phn[2].$dsh.$phn[3].$phn[4].$phn[5].$dsh.$phn[6].$phn[7].$phn[8].$phn[9];

             $sql1 ="select Lname, Fname from Customers where Phone =

'$Phn' ";

             $result1 = mysqli_query($cxn, $sql1);
             if(!$result)
             {

?>

                 <div align="center">

                 <strong>No Match Found</strong>
                 <br /><br />
                 </div>

<?php

             }

?>

             <div align="center">
             <table border="4" cellpadding="5" cellspacing="55"

rules="all" frame="box">

             <tr class='heading'>
             <th>Last Name</th>
             <th>First Name</th>

<?php

             while($row1 = mysqli_fetch_row($result1))
             {

                 $Lname     = $row1[0];
                 $Fname     = $row1[1];

?>              <tr>
                 <td> <?php echo $Lname; ?> </td>
                 <td> <?php echo $Fname; ?> </td>
                 </tr>

<?php

               }

?>

               </table>
             </div>>
         </body>

</html> As you [those that replied] accurately noted, the problem was with the quoting. I appreciate all your comments, take them seriously and will use the information contained in them for future programming. No matter how much skill in programming I have, I will remain a NEWBIE; ie, someone who wishes to grrow in knowledge and acknowledges that there are many programmers much more skilled than I. Thanks again. Ethan happy to hear you got it working. Sad to see that you didn't heed the tips provided to you and alter your code, and that you still have errors in it. oh, well....