Re: VAR_DUMP INTO PHP VARIABLES

My error! This: $responseCode = $result[return]['responsecode']; should have been $responseCode = $result['return']['responsecode']; The other responses have been rather more elegant, though I think my solution is a little more readable - i.e., I had to think about what was happening for those ones! Toby On 6/19/2014 9:50 AM, Oriole Computing wrote:

Hi Toby, my response is in variable $result so i run the code as below $responseCode = $result[return]['responsecode']; but getting this error: PHP Parse error: syntax error, unexpected T_RETURN, expecting '] Warm Regards *SUPPORT TEAMORIOLE COMPUTING* *1938 B1 MUNGWI ROAD* *LUSAKAZAMBIA* *Skype:* oriolecomputing | *Url:* oriolecomputing.blogspot.com <http://generalcomputing.blogspot.com/> On Thu, Jun 19, 2014 at 12:23 PM, Pritoj Singh <pritojs@gmail.com> wrote:

foreach($arr['return'] as $key=>$val){ $$key=$val; } On Thu, Jun 19, 2014 at 3:48 PM, Toby Hart Dyke <toby@hartdyke.com> wrote:

If you have the response in a variable, $response: $responseCode = $response[return]['responsecode']; $responseMessage = $response[return]['responseMessage']; $transactionID = $response[return]['transactionID'];