Re: Waiting for localhost
| From: | Karl DeSaulniers | Date: | Thu, 02 Apr 2015 03:41:05 +0000 |
| Subject: | Re: Waiting for localhost | ||
| References: | 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-48997@lists.php.net to get a copy of this message | ||
Question to list, since I have not had to venture to the mysqli territory just yet,
but is it proper to use mysql_error() with mysqli transactions?
This may be what your missing Ethan.
mysql_error() looks for a mysql_ transactions doesn't it?
Or are they interchangeable?
Best,
Karl DeSaulniers
Design Drumm
http://designdrumm.com
On Apr 1, 2015, at 10:35 PM, Ethan Rosenberg <erosenberg@hygeiabiomedical.com> wrote:
>>>
> <snip>
>
> Richard -
>
> Thanks.
>
> The problem is in the database connection.
>
> from MySQL
>
> mysql> show tables;
> +-----------------+
> | Tables_in_Store |
> +-----------------+
> | Charges |
> | Customers |
> | Food |
> | Inventory |
> | Orders |
> | Purchases |
> +-----------------+
>
> This code works...
>
> $hostname="localhost";
> $database="Store";
> $username="ethan";
> $password="xxxxx";
>
>
> $link = mysqli_connect($hostname, $username, $password);
> if (!$link) {
> die('Connection failed: ' . mysql_error());
> }
> else{
> echo "Connection to MySQL server " .$hostname . " successful!
> " . PHP_EOL;
> }
>
> $db_selected = mysqli_select_db($link, $database);
> if (!$db_selected) {
> die ('Can\'t select database: ' . mysql_error());
> }
> else {
> echo 'Database ' . $database . ' successfully selected!';
> }
>
> $sql1 = "show tables";
> $result1 = mysqli_query($link, $sql1);
> $row1 = mysqli_fetch_array($result1);
> echo 'row1<br />';
> print_r($row1);
>
> BUT
>
> The output is ....
>
> Connection to MySQL server localhost successful! Database Store successfully selected!
> row1
> Array ( [0] => Charges [Tables_in_Store] => Charges )
>
> What am I missing??
>
> TIA
>
> Ethan
>
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