Re: MYSQL error

From: Date: Wed, 21 Jun 2000 22:12:01 +0000
Subject: Re: MYSQL error
Groups: php.db 
Request: Send a blank email to php-db+get-560@lists.php.net to get a copy of this message
Addressed to: "clayton collie" <ccollie@cau.edu> php-db@lists.php.net ** Reply to note from "clayton collie" <ccollie@cau.edu> Wed, 21 Jun 2000 05:57:12 -0400 > > can someone tell me whats wrong with this query ? im using MYSQL > 3.22.22, so i cant do a condition on an inner join (hence the left > join). MySQL complains about a syntax error. > > select u.UserId, u.LastName, u.FirstName, ts.TestName, ts.Score, > ts.StartDate, ts.StartTime, ts.TimeSpent, > from users u, test_scores ts > left join users on (u.UserId = ts.UserId) A couple of things... 1. There is no , after the last item in the list 2. You are mixing two join syntaxes. one would go like this: SELECT u.UserId, u.LastName, u.FirstName, ts.TestName, ts.Score, ts.StartDate, ts.StartTime, ts.TimeSpent FROM users u, test_scores ts WHERE u.UserId = ts.UserId Only records in both tables will appear in the result set The other would be this: SELECT u.UserId, u.LastName, u.FirstName, ts.TestName, ts.Score, ts.StartDate, ts.StartTime, ts.TimeSpent FROM test_scores ts LEFT JOIN users u on (u.UserId = ts.UserId) Or possibly this: SELECT u.UserId, u.LastName, u.FirstName, ts.TestName, ts.Score, ts.StartDate, ts.StartTime, ts.TimeSpent FROM test_scores ts LEFT JOIN users u USING ( UserId ) All records in test_scores will appear in the result, with fields from users null if no matching users entry exists. Rick Widmer Internet Marketing Specialists www.developersdesk.com

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