Re: Desperate Help needed

From: Date: Sun, 14 Jan 2001 17:05:05 +0000
Subject: Re: Desperate Help needed
References: 1  Groups: php.db 
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Set up an expire time... if a user hasn't accessed the page showing the room's activity (where all the messages are shown) within, say, 3 minutes, then the next request that comes in, regardless of who makes it, should remove the timed-out user from the list. It's important, of course, to make sure all of the chat windows are refreshing faster than your timeout value; a refresh rate of 3 minutes or more wouldn't be very convenient anyway ;) --Toby ----- Original Message ----- From: "sarahana" <sarahana@cyberjunkie.com> To: <php-db@lists.php.net> Sent: Sunday, January 14, 2001 11:04 AM Subject: [PHP-DB] Desperate Help needed Hi, I made a database chatroom that seemed to be working perfectly fine - now, it seems, if more than two people log in, the 1st person of the three automatically gets logged out - its because i tried to make an automatic log off for those who cross the window.... How do you detect if a person has closed the window (hence killing the cookie) without logging off (so the database still has him listed, and therefore is shown to be online)? Here's the scenario: 1. one table lists the chatters' names 2. second table has 25 rows for each messages, they keep getting replaced as the new messages come in the problem: the chatters table lists those users who logged out ages ago... thanks.

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