RE: [PHP-DB] Error prevention
| From: | Michael Rudel | Date: | Tue, 13 Mar 2001 16:17:46 +0000 |
| Subject: | RE: [PHP-DB] Error prevention | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-7406@lists.php.net to get a copy of this message | ||
Hi Martin,
... you forgot to 'mysql_fetch_row' or 'mysql_result'. Read about it in
the PHP-Manual in the MySQL Functions.
Greetinx,
Mike
Michael Rudel
- Web-Development, Systemadministration -
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-----Original Message-----
From: Martin Skjöldebrand [mailto:chimbis@skjoldebrand.org]
Sent: Tuesday, March 13, 2001 5:05 PM
To: php-db@lists.php.net
Subject: [PHP-DB] Error prevention
I'm baffled (again ....)
In my mql database I'm doing:
SELECT cl_login FROM client WHERE cl_login = "xxx";
and if "xxx" exists I get the result xxx while if it doesn't exist I get an
empty string.
In PHP I'm doing
$querytest = "SELECT cl_login FROM client WHERE cl_login = '$txtLogin';";
$testresult = mysql_query($querytest, $mysql_link);
if ($testresult) {
print "Error: Client already in database.";
exit;
}
Now, no matter what* I still get a result of the query: Resource id # 7
(i put in echo $testresult; when the routine didn't work).
* That I get Resource id ... if I have a cl_login = xxx or if I don't have
one.
What's !¤#!"#¤ going? How do I check for a duplicate before writing it to
the database? (Short of putting UNIQUE on the table, which I suppose would
result in an error).
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